The most streamlined amount of lowercase

xiaoxiao2021-03-06  25

The test passed.

FUNCTION

Numtochar

(

Const

n

:

REAL

):

String

;

/ / Can get trillion, and you can expand

Const

CNUM

:

WideString

=

'Zero 壹 肆 柒捌 柒捌 - 万 仟 佰 佰 万 万 佰 元 分

;

Ccha

:

array

[

0..1

,

0..12

]

Of

String

=

(("

'元'

,

'Zero pick'

,

'佰'

,

'Zero'

,

'万'

,

'零'

,

'hundreds of millions'

,

'Zero zero'

,

'Zero'

,

'万'

,

'零'

,

'hundreds of millions'

,

'元'

),

(

'yuan'

,

'zero'

,

'zero'

,

'zero'

,

'Wan'

,

'Billion'

,

'Billion'

,

'zero'

,

'zero'

,

'Wan'

,

'Billion'

,

'Billion'

,

'yuan'

));

VAR

i

:

Integer

;

Snum

,

STEMP

:

WideString

;

Begin

Result

: =

'' '

;

Snum

: =

Format

(

'% 15d'

, [

Round

(

n

*

100

);

for

i

: =

0

TO

14

DO

Begin

STEMP

: =

Copy

(

Snum

,

i

1

,

1

);

IF

STEMP

=

'' '

THEN

Continue

Else

Result

: =

Result

CNUM

[

Strtoint

(

STEMP

)

1

]

CNUM

[

i

13

];

end

;

for

i

: =

0

TO

12

DO

Result

: =

StringReplace

(

Result

,

Ccha

[

0

,

i

],

Ccha

[

1

,

i

],

[

RFREPLACEAll

]);

IF

POS

(

'Zero'

,

Result

) =

0

THEN

Result

: =

StringReplace

(

Result

,

'Zero angle'

,

'zero'

,

[

RFREPLACEAll

])

Else

Result

: =

StringReplace

(

Result

,

'Zero angle'

,

'whole'

,

[

RFREPLACEAll

]);

Result

: =

StringReplace

(

Result

,

'Zero'

,

'' '

,

[

RFREPLACEAll

]);

end

;

2. I have no testing this.

FUNCTION

Changdx2

(

mmje

:

Double

):

String

;

Const

S1

:

String

=

'Zero Zhai 叁 肆 柒捌 柒捌'

;

S2

:

String

=

'Different angle pickers 佰 万 万 万 万 万;;

FUNCTION

Strtran

(

Const

S

,

S1

,

S2

:

String

):

String

;

Begin

Result

: =

StringReplace

(

S

,

S1

,

S2

,

[

RFREPLACEAll

]);

end

;

VAR

s

,

DX

:

String

;

i

,

Len

:

Integer

;

Begin

IF

mmje

<

0

THEN

Begin

DX

: =

'negative'

;

mmje

: =

-

mmje

;

end

;

s

: =

Format

(

'% .0f'

,

[

mmje

*

100

]);

Len

: =

Length

(

s

);

for

i

: =

1

TO

Len

DO

DX

: =

DX

Copy

(

S1

,

(

ORD

(

s

[

i

])

-

ORD

(

'0'

))

2

1

,

2

)

Copy

(

S2

,

(

Len

-

i

) *

2

1

,

2

);

DX

: =

Strtran

(

Strtran

(

Strtran

(

Strtran

(

Strtran

(

DX

,

'Zero'

,

'zero'

),

'佰'

,

'zero'

),

'Zero pick'

,

'zero'

),

'Zero angle'

,

'zero'

),

'Zero'

,

'whole'

);

DX

: =

Strtran

(

Strtran

(

Strtran

(

Strtran

(

Strtran

(

DX

,

'Zero'

,

'zero'

),

'Zero'

,

'zero'

),

'零'

,

'Billion'

),

'万'

,

'Wan'

),

'元'

,

'yuan'

);

IF

DX

=

'whole'

THEN

Result

: =

'Zero yuan'

Else

Result

: =

Strtran

(

Strtran

(

DX

,

'hundreds of millions'

,

'Billion'

),

'Zeroide

,

'whole'

);

end

;

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